Question

Let g(x)=2x and h(x)=x^2+4
evaluate (h o g)(-2)

Answer 1

always start by getting rid of the \(\circ\) notation and rewrite as
\[h\circ g(-2)=h(g(-2))\]

Answer 2

-16?

Answer 3

no lets go slow

Answer 4

in order to compute \(h(g(-2))\) you first have to find \(g(-2)\)

Answer 5

if \(g(x)=2x\) then what is \(g(-2)\) ?

Answer 6

-2x

Answer 7

\(g(-2)\) is a number, no \(x\) in your answer

Answer 8

\[g(x)=2x\] makes \[g(-2)=2\times (-2)=-4\]

Answer 9

your final job is to find \(h(-4)\)