Question

Given: x + y = 15.

Which of the following are ordered pairs of this equation?


{(-3, 14),(0, 15),(3, 16)}
{(-3, 16),(0, 15),(3, 14)}
{(16, -3),(15, 0),(14, 3)}

Answer 1

Well, just pick the set containing pairs that when you add up, equal 15.

Answer 2

Consider the first one... it's not your answer, because it has the pair (-3, 14)
which, when you add up...
\[\large -3 + 14 = 11 \ne 15\]

Answer 3

in that case none of these are right @terenzreignz

Answer 4

Are these sets of three pairs?

Answer 5

or 9 individual pairs?

Answer 6

sets of three pairs @terenzreignz

Answer 7

Then in that case, none of these would be right...

Answer 8

i forgot to put the 1/3 infront of x my bad @terenzreignz

Answer 9

<eye twitching>

Answer 10

lol just answer the question kml @terenzreignz

Answer 11

Well, in that case, what you do is just plug in, instead of adding...
\[\Large \frac13x + y = 15\]

Answer 12

For instance, that first set again... is not the solution, because when we plug in (-3 , 14)
x = -3
y = 14
\[\Large \frac13(-3)+14 = -1 + 14 = 13 \ne15\]

Answer 13

um i dont know how to do that yeah mhm so tell me @terenzreignz

Answer 14

Okay, again... step-by-step...
let's test out the first point of the first set of three points...

That would be (-3, 14)
So
x = -3
and
y = 14

Let's test it out on
\[\Large \frac13\color{red}x+\color{blue}y=15\]

Answer 15

\[\Large \frac13(\color{red}{-3})+\color{blue}{14}\]\[\Large = -1+14\]\[\Large = 13\]\[\Large \ne 15\]

We need it to be 15, but this pair doesn't fit.
Hence, the first set isn't the answer :P

Answer 16

oooook i get it now thank ya sweetie @terenzreignz

Answer 17

It's 'Terence', sweetie :P
And no problem, now tell me your answer :3

Answer 18

ok smarty but i ended up with with the last set @terenzreignz

Answer 19

It's Terence -.-

And really now?
I fail to see how even the pair (16 , -3) fits into all of this...

Answer 20

The pair (16, -3) is in the last set, no?
x = 16
y = -3
\[\Large \frac13\color{red}x+\color{blue}y=15\]
\[\Large \frac13(\color{red}{16})\color{blue}{-3}=15\]\[\Large \color{green}{\frac{7}{3}}=15\]

Answer 21

clearly not true... *sweetie* :P

Answer 22

never mind its the second one i freaked up and put x and y in parentheses an did that first @terenzreignz

Answer 23

Okay, well, since I already said the first and last were wrong, it has to be the second one, *sweetie*

Good job anyway :P

Answer 24

i wasn't even looking at that TERENCE @terenzreignz

Answer 25

U mad? LOL
Peace ^_^

Answer 26

k bye kml @terenzreignz

Answer 27

this ended up being wrong TERENCE @terenzreigns

Answer 28

Impossible, unless there was something you forgot to put up again...

Answer 29

thats what i thought so i worked it out step by step and i still got the same answer these people must be dumb or its something i'm missing @terenzreignz

Answer 30

Interestingly, what was apparently the correct answer?

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