i have problem in mathematical induction!!
can anybody help me

Question

hartnn · Answer

waiting for it ...

anonymous · Answer

nt undrstng anything 4m it... can anybody plzz help me!!

hartnn · Answer

do you have a specif problem you have trouble with ... ? 
with an example it will be easier to understand...

hartnn · Answer

basically 3 steps, 
1) prove the result for n = 1
2) assume the result is true for n=k 
3) prove the result for n=k+1

anonymous · Answer

1+3+32+……+ 3n- 1= (3n- 1)divided by 2

anonymous · Answer

how to put (k+1) that the prblm!!

hartnn · Answer

you sure its, 1+3+32... ??? 
can you post the problem more clearly ?

anonymous · Answer

yup...it exctally that only!!

blurbendy · Answer

strange sequence..

anonymous · Answer

plzz help me ... i have my exam 2mrw moring!!

ganeshie8 · Answer

$\large 1+3+3^2 + .... + 3^{n-1} = \frac{3^{n-1}-1}{2}$

ganeshie8 · Answer

its like that ?

anonymous · Answer

nopes!!

ganeshie8 · Answer

ok strange sequence it is !

anonymous · Answer

i knw!!

hartnn · Answer

i don't even see a sequence...

anonymous · Answer

bt its written like that only!! :-(

hartnn · Answer

it must be 
$\large 1+3+3^2 + .... + 3^{n-1} = \frac{3^{n}-1}{2}$

ganeshie8 · Answer

if $a_n =  3n- 1$

then

$a_1 = 3(1) - 1 = 2$

but in your sequence the first term is 1, so it makes no sense

anonymous · Answer

one more question..
$$x^{2n} - y ^{2n} is disible by x+y$$

hartnn · Answer

the earlier one is $\large 1+3+3^2 + .... + 3^{n-1} = \frac{3^{n}-1}{2}$
only....
for 2nd problem, 
could you prove it for n=1 ?

hartnn · Answer

if you want we can guide you for $\large 1+3+3^2 + .... + 3^{n-1} = \frac{3^{n}-1}{2}$ sequence..

anonymous · Answer

yup sure bt in ma paper is like what i had post after..
okey..
bt how to put (k+1)

hartnn · Answer

ok, lets talk about only one 1st one, first
for n=1, LHS =RHS = 1 is easy 

we assume that 
$\large 1+3+3^2 + .... + 3^{k-1} = \frac{3^{k}-1}{2}$
is true . 

now replace k by k+1 

now we have to prove 
$\large 1+3+3^2 + .... + 3^{k} = \frac{3^{k+1}-1}{2}$
ok?

anonymous · Answer

yup.. thnks u lot!!

hartnn · Answer

can you prove that or need help with that ?

anonymous · Answer

no thnks... i cn do it!!

hartnn · Answer

good!

anonymous · Answer

hmm... o.O

anonymous · Answer

.