Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bar sells for $6.00 per pound and the milk chocolate fudge bar sells for $4.00 per pound. You purchased a combination of these bars for all of your family and friends for the holidays and your bill came to $120. This scenario can be modeled by the equation 6d + 4m = 120. Which of the following is not a possible combination of dark chocolate bars and milk chocolate bars?
Helpp
Okay...."which of the following" So what are your answer choices?
A.10 dark bars and 15 milk bars B. 12 dark bars and 12 milk bars C.14 dark bars and 18 milk bars D, 6 dark bars and 21 milk bars
Okay...your equation \[6d + 4m = 120\] What you do is take your answer choices...and plug them into your equation *I'll do 1 example for A* 10 dark bars and 15 milk bars \[6d + 4m = 120\] 'd' gets replaced by 10...and 'm' gets replaced with 15 \[6(10) + 4(15) = 120\] Now we simplify \[60 + 60 = 120\] \[120 = 120\] So this one works out...and is NOT your answer..but this is how you would solve this problem...just test the other choices
ahh ok iget it now thanks
No problem!
Join our real-time social learning platform and learn together with your friends!