Question

...

Answer 1

by the inscribed angle theorem, angle BAC is exactly half of angle BOC

Answer 2

BAC = (1/2)*BOC

BAC = (1/2)*60

BAC = 30 degrees

Answer 3

can you help with this one too?

Answer 4

sure

Answer 5

one sec

Answer 6

angle COA = 2*(angle ACB)

angle COA = 2*(35)

angle COA = 70

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angle CEA = (1/2)*angle COA

angle CEA = (1/2)*70

angle CEA = 35

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arc CE + arc EAC = 360

arc CE + 278 = 360

arc CE = 360 - 278

arc CE = 82

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angle CAE = (1/2)*arc CE

angle CAE = (1/2)*82

angle CAE = 41

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angle CAE + angle CEA + angle ACE = 180

41 + 35 + angle ACE = 180

76 + angle ACE = 180

angle ACE = 180 - 76

angle ACE = 104


...ok that's a lot to take in, but I couldn't think of any easier way sadly

Answer 7

OMG thank you so much!!!

Answer 8

you're welcome, hopefully it all makes sense (or most of it does lol)

Answer 9

haha yeah a lot of it makes sence

Answer 10

ok great