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giving a medal ! => Log52 + log510 – log54 ( the 5's are subscrips)))
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So is this the question: \[\log_5 2 + \log_5 10 - \log_5 4\]
yes
we have to divide right because the log only knows the base of 10 right?
.9999999999? is that right? <=
Since they're all the same base, we can combine these into one log. When we have logs added together, we can put them in one log by multiplying whats inside. So for the first two logs, we can combine them like this: \[\log_5 (2 \times 10) - \log_5 4\] \[\log_5 20 - \log_5 4\]
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When we subtract logs, we divide whats inside. So we can make this into one log like this: \[\log_5 5\]Since the base is the same as the stuff inside, the answer is just 1, since 5^1 = 5.
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