Find the standard form of the equation of the parabola with a focus at (0, -8) and a directrix at y = 8.
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OpenStudy (anonymous):
@BulletWithButterflyWings
OpenStudy (anonymous):
@lncognlto do you get it? or are you able to explain it to me?
OpenStudy (lncognlto):
I'm sorry, Chandler, I don't know about focus and directx off the top of my head. I can look it up, but it might take a little while... Do you want me to?
OpenStudy (anonymous):
Eh I'm sure there is one person that does. Don't worry about it. Thanks though! @lncognlto
OpenStudy (anonymous):
@Shikanu
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OpenStudy (lncognlto):
Cool cool :)
OpenStudy (anonymous):
@nincompoop
OpenStudy (anonymous):
@nincompoop
OpenStudy (campbell_st):
the general form is
\[x^2 = -4ay\]
since the directrix is above the focus
well the distance between the focus and directrix is 2a
so 16 = 2a, so a = 8
substitute it into the equation.
and you get the parabola
OpenStudy (anonymous):
Thank you!! @campbell_st
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OpenStudy (anonymous):
so wait I will get x^2 = -4(8)y ?
OpenStudy (anonymous):
giving me x^2 = -32y?
OpenStudy (anonymous):
Now what?... @campbell_st
OpenStudy (campbell_st):
thats the equation or it can be written as
y = -1/32 x^2