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Mathematics 8 Online
OpenStudy (anonymous):

What is the equation of the following graph? Use ^ for exponents. Use parenthesis where necessary. MEDAL AWARD! PLEASE HELP! GRAPH BELOW!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

@seraphic_topaz

OpenStudy (anonymous):

@NoelGreco

OpenStudy (anonymous):

@ineedhelpnow08

OpenStudy (anonymous):

@Loser66

OpenStudy (anonymous):

PLEASEEE ):

OpenStudy (anonymous):

Do you have answer options to go with this graph?

OpenStudy (loser66):

@jdoe0001

OpenStudy (anonymous):

no i dont ): free response

OpenStudy (anonymous):

please help i need it asap

OpenStudy (loser66):

it 's hyperbola with center (1,2)

OpenStudy (loser66):

give me few second, I have to look up at my note, cannot give you a wrong answer

OpenStudy (loser66):

thanks @jdoe0001 take it over, please

OpenStudy (anonymous):

thanks.

OpenStudy (jdoe0001):

it's a hyperbola let's take a peek at the vertices, the "humps" coordinates (-4, 2) and (6, 2) the distance between both points is, well, from -4 over the x-axis to the 6, is 10 units the "a" component will be half of that, so a = 5 looking at the green rectangle, smaller side is the length of the "conjugate axis" which is where the component "b" is looking at the distance over the y-axis, it goes from 0 to 4, so is 4 units long "b" component will be half that, so b = 2 the center of the hyperbola will be half-way between the vertices of either axis so moving from the vertex on the left, at (-4, 2) by 5 units, "a" value we'd end up at (1, 2) so the center is at (1, 2)

OpenStudy (anonymous):

but how do i put that into a equation for the graph?

OpenStudy (jdoe0001):

keeping in mind that this hyperbola is opening over the x-axis, or is horizontal so the fraction with the "x" variable will be the POSITIVE one thus the equation for the hyperbola will be \(\bf \cfrac{(x-h)^2}{a^2}-\cfrac{(y-k)^2}{b^2}=1\)

OpenStudy (jdoe0001):

your center at (h, k) of course

OpenStudy (anonymous):

what is a and b then?

OpenStudy (anonymous):

ohhh 5 and 2?

OpenStudy (jdoe0001):

yes

OpenStudy (anonymous):

What is the equation of a parabola with vertex (0, 0) and directrix x = -3. could you help me with this one?

OpenStudy (anonymous):

@jdoe0001

OpenStudy (anonymous):

Is there a name for the green rectangle? How do I typically identify it in a similar problem?

OpenStudy (jdoe0001):

hmm so, the vertex is the origin and the directrix is -3 that means the focus is the opposite end, th same distance as the directrix, that is |dw:1374448109466:dw|

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