@GoldEverything You're really helpful, could you help me with this one too? Dan is making a border for a triangular placemat. He wants it to have side lengths of A=8 in. and B=4 in. If the measure of angle C= 50 degrees, how many different placemats can Dan make? a. 0 b. 1
They're basically asking if they can make a triangle witht he given triangle hence the number of placemats.
I think the answer is 1, is that right?
|dw:1374459833792:dw| A triangle has 6 parts, 3 angles (the uppercase letters) and 3 sides (the lowercase letters) and anyways if we have sides a=8 and b=4 and the angle in cluded (C is the angle between sides a and b) is 50 degrees .
|dw:1374459951753:dw|
K, thanks for the triangles.
Is the answer 1?
I would presume, is this multiple choice?
Yes, it is
You would have to find the third sidee (c) with the law of cosines c² = a² + c² - 2bc cosC
Cool, thanks for the help.
\[c^2=4^2+8^2-2(4)(8)(\cos 50)\]
sorry i was so late hopefully pie helped you out really well
I got C=6.23
@GoldEverything, it's okay! Thanks so much for the help earlier! Pie is really helping out!
Ok, and since you got a value for c tyou now have to try this theorem, two of the sides of the traingle have to be greater than the last side so in other words
a=4 b=8 c=6.23 a+b>c a+c>b b+c>a
If any of those aren't true, then you dont have a triangle and so its - and if they all works then you have 1 triangle, tell me what you get for each
Cool. Solving it right now!
12> 6.23, So that's true. 10.23> 8, So that's true. 14.23> 4 So there is one triangle
I get it now, thanks for all the help.
Yep, so that's your answer, if you enjoyed my experience with me, be sure to fan and write something while you're at it =), also just let me know if you need anymore help
Okay, thanks again. :)
sorry again for being late if you need any more help just ask me or my friend @doulikepiecauseidont
It's fine! :) Will do! You both have really helped!
thats the point for open study were just working my the code of conduct
Haha yea
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