Please help me understand finding the value of logarithms.
a. log(2)16
b. log(5)25
c. log(4)64
d. log(5)625

Question

Please help me understand finding the value of logarithms.
a. log(2)16
b. log(5)25
c. log(4)64
d. log(5)625

e.mccormick · Answer

Are you looking for a way to aproximate it with a calculator or what?

blurbendy · Answer

These can be solved by simplifying things into exponents.

i.e.
log(2)16 =

log(2)2^4

= 4

anonymous · Answer

To know how to solve it with and without the calculator.

zzr0ck3r · Answer

um this depends on the base of the log

zzr0ck3r · Answer

should that say$$\log_{2}(16)? $$

anonymous · Answer

Yes

zzr0ck3r · Answer

another way of saying that is
2^? = 16

e.mccormick · Answer

Because of what a log is:
$y=b^x\implies \log_b(y)=x$

Sometimes you can rearrange things to solve them.

mertsj · Answer

You need to know that the log is the exponent so when a problem asks you to find a log, it is asking you to find an exponent.

zzr0ck3r · Answer

5^? = 25

anonymous · Answer

Oh I get it now, thank-you

zzr0ck3r · Answer

4^? = 64

mertsj · Answer

Look at the first problem.  It tells you that the base is 2 and the answer is 16.  You are supposed to give the exponent that goes on the base 2 so that the answer will be 16.

anonymous · Answer

So 4, 5, 16, 125

mertsj · Answer

no.

mertsj · Answer

Look at the second problem.  The base is 5.  The answer is 25.  What is the exponent that you would put on the base 5 to get an answer of 25?