Question

how do you find the limit:

lim ln(1+x)
x->0 --------
1 + x

Answer 1

I don't see any reason you can't just plug in 0 and evaluate

Answer 2

So you'll get this:
\[\frac{ \ln(1+0) }{ 1+0 }=\frac{ \ln1 }{ 1 }=\ln 1=?\]

Answer 3

oh, okay I gotcha. Thank you!

Answer 4

You're welcome, glad I could help