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Logarithms Equations.
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\[\log_{6}(x+2)+\log_{6}(x-3)=1 \]
So we have logbase6(x^2-x-6)=1
then I get a little stuck
do we take the log of 1, as logbase6(1)
good now what is 6^1 = x^2 -x -6?
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6, so I bring it over a factor the trinomial?
yes you will factor 0= x^2 -x -12...
x^2-x-12? And the reason it becomes an linear equation is because we took the same log bases?
Its not linear... But the law of logarithms is applied to get to the 6^1... the rest is the quadratic formula.
oh my mistake, but we can work with it because it has the same log bases
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yes... complete the rest its easy...
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