Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Logarithms Equations.

OpenStudy (anonymous):

\[\log_{6}(x+2)+\log_{6}(x-3)=1 \]

OpenStudy (anonymous):

So we have logbase6(x^2-x-6)=1

OpenStudy (anonymous):

then I get a little stuck

OpenStudy (anonymous):

do we take the log of 1, as logbase6(1)

OpenStudy (anonymous):

good now what is 6^1 = x^2 -x -6?

OpenStudy (anonymous):

6, so I bring it over a factor the trinomial?

OpenStudy (anonymous):

yes you will factor 0= x^2 -x -12...

OpenStudy (anonymous):

x^2-x-12? And the reason it becomes an linear equation is because we took the same log bases?

OpenStudy (anonymous):

Its not linear... But the law of logarithms is applied to get to the 6^1... the rest is the quadratic formula.

OpenStudy (anonymous):

oh my mistake, but we can work with it because it has the same log bases

OpenStudy (anonymous):

yes... complete the rest its easy...

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!