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Sampling and Data 8 Online
OpenStudy (sivapriya):

A simple random sample of 400 households is taken in a large city, and the number of cars in each sampled household is noted. The average number of cars in the sampled households is 1.8 and the SD is 1.3. Among the sampled households, 10% had no car. An approximate 99% confidence interval for the percent of city households that have no car goes from _____________________% to ______________________%.

OpenStudy (anonymous):

you have the interval from -2.575 to +2.575

OpenStudy (anonymous):

(this is not the answer). in this interval you have the 99% of city households that have no car

OpenStudy (anonymous):

10% have no car, so =40

OpenStudy (anonymous):

I don't understand what you wrote... Let's see: if we go with 10% to the "SticiGui", we get -1.28, isn't it? But the problem here now is that we are considering percent intervals, not value intervals. So how can we calculate them? (%1,%2)

OpenStudy (anonymous):

@asjara i do not know. I am thinking about... nice approach. 10% is -+ 0.126 Isnt it?

OpenStudy (anonymous):

1st part answer is 1.6934 to 1.9064.

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