Find the quotient of the quantity negative 5 times x to the 3rd power plus 20 times x to the 2nd power minus 25 times x all over negative 5 times x.

Question

anonymous · Answer

−5x^3 + 20x^2 + 5

 x^2 − 4x + 5

 −x^2 − 4x + 5

 x^2 + 4x − 5

johnweldon1993 · Answer

$$\large \frac{ -5x^3 + 20x^2 - 25x }{ -5x }$$

If you can answer these 3 questions you can answer the question

what is:

$$\large \frac{ -5x^3 }{ 5x } = \space ?$$

$$\large \frac{ 20x^2 }{ 5x } = \space ?$$

$$\large \frac{ -25x }{ 5x } = \space ?$$

anonymous · Answer

hm I remember u telling me something about this

anonymous · Answer

Forgot to write that down on my notes since i dont have this one to slove for it

johnweldon1993 · Answer

Right we went over something very similar...

okay take it step by step

$$\large \frac{ -5x^3 }{ -5x } = \frac{ -5 }{ -5 } \times \frac{ x^3 }{ x }$$

remember you can just break everything up like that...so what is -5/-5?    and what is x^3/x?

*hint...when dividing exponents with the same base (x^3/x) you leave the base alone (x) and subtract the exponents (3 - 1)

anonymous · Answer

5^3-1? = 5^2

anonymous · Answer

@johnweldon1993

johnweldon1993 · Answer

Close but you forgot the first part -5/-5

$$\large \frac{ -5x^3 }{ -5x } = x^2$$

Make sense there?