Question

The price p and the quantity x sold of a certain product obey the demand equation
x=-20p+500, 0≤p≤25
a.Express the revenue R as a function of x. (Hint: R = xp, where p is the unit price.)
b.What is the revenue if 20 units are sold?
c.How many of this item should be sold in order to get maximum revenue?
d.What is the maximum revenue?
e.The marginal revenue.
f.The marginal revenue at x = 100
@cruffo

Answer 1

a.) R = xp = p(-20p + 500) = distribute...

Answer 2

p = unit price
x = quantity
b.) want R when x = 20
solve for p: 20 = -20p + 500
then plug that # in for p in the R function you got in part (a).

Answer 3

i didnt get the R FUCTION can u work it out for me..

Answer 4

just multiple p(-20p + 500)

Answer 5

that will give me 20p^2 + 500p

Answer 6

good.

Answer 7

why did u do it that way..cos i have to show working for that

Answer 8

beautiful