Question

H(t)=-16t^2+vt+s what is maximum height? I forgot to say that the initial velocity is 34 per second

Answer 1

For the maximum height recall that your velocity = 0

so take the derivate of that function for velocity.
\[\frac{ dH }{ dt } = -32t + v\]

make the derivate = 0 and solve for time

sub back the time in the max height equation.

H(t).