Question

please help ): Factor completely: 3x^2 + 10x + 3

prime
(3x + 3)(x + 1)
(3x + 1)(x + 3)
(3x − 1)(x − 3)

Answer 1

the first coefficient is 3

the last term is 3

they multiply to 3*3 = 9

Answer 2

what two numbers

a) multiply to 9

AND

b) add to 10

Answer 3

um im not sure this really confuses me ): @jim_thompson5910

Answer 4

list out the ways to multiply two numbers to get 9

1*9
3*3

which of those pairs add to 10?

Answer 5

it's not prime uri

Answer 6

3x1=3
3+1=4 @jim_thompson5910

Answer 7

idk what you're referring to exactly

Answer 8

oh you're looking at the answer choices

Answer 9

Hm middle term breaking.

Answer 10

Ya actually..

Answer 11

well that trick only works if both leading coefficients for the binomial factors are 1

Answer 12

im confused so is it prime?

Answer 13

Looking at her options it's Prime.

Answer 14

9 and 1 multiply to 9 and add to 10

Answer 15

so

3x^2 + 10x + 3

breaks into

3x^2 + 9x + x + 3

now factor by grouping

Answer 16

+ 10x + 3<== We look at this..

Answer 17

9x1=9 not 3.

Answer 18

uri it's not prime

Answer 19

lol.

Answer 20

2x^2 − 6x − 20

(2x − 10)(x + 2)

(x − 5)(2x + 4)

2(x − 5)(x + 2)

prime

is this one prime too?

Answer 21

How are you getting 9x +x when there should be a integral which when adding or subracting should be 10 and muliplying 3 @jim_thompson5910

Answer 22

3 doesn't come in any table except 3 x1 =3

Answer 23

Maybe I'm wrong...idk..@jim_thompson5910 is a genius.

Answer 24

99 SS lol

Answer 25

Break up 10x into 9x+x, then factor by grouping


3x^2 + 10x + 3

3x^2 + 9x + x + 3

(3x^2 + 9x) + (x+3)

3x(x + 3) + 1(x+3)

(3x + 1)(x + 3)

Answer 26

2x^2 − 6x − 20

find the common..that is 2
2(x^2-3x-10)

Answer 27

I'm not aware of grouping method..

Answer 28

I was doing the simple factorization..