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Chemistry 26 Online
OpenStudy (anonymous):

Calculate the pH of a solution that results from mixing 44.7 mL of 0.165 M ammonia with 22.6 mL of 0.109 M ammonium chloride. The Kb value for NH3 is 1.8 x 10-5.

OpenStudy (anonymous):

What is the buffer component ratio, ([NO2-]/[HNO2]) of a nitrite buffer that has a pH of 3.98. Ka of HNO2 is 7.1 x 10-4. For this one ^^ I tried base10^-3.98 divided by the ka to get concentration but....

OpenStudy (anonymous):

And the problem for the NH3 Nh4 problem i dont know if i set up a start change AN chart after finding new concentrations.

OpenStudy (anonymous):

@pengembara_bumi1

OpenStudy (anonymous):

hold on :)

OpenStudy (anonymous):

@Frostbite @Krishnadas @dumbsearch2

OpenStudy (frostbite):

Sounds like a Henderson-Hasselbalch problem.

OpenStudy (anonymous):

But the things is, Im not supposed to use that equation! :/ Im supposed to set up a reaction and etc and use the ka to find concentrartion of poh then ph (for the nh3 nh4 problem)

OpenStudy (anonymous):

buttt I dont know what type of reaction im supposed to go off of. is it NH3 +h20 <--> OH- + NH4

OpenStudy (anonymous):

or NH3+NH4 or ....??

OpenStudy (anonymous):

ok i will try that

OpenStudy (anonymous):

Ka? Usually ahaha.

OpenStudy (anonymous):

@jennilalala : look at the equations i had given :) mybe it can help u

OpenStudy (anonymous):

so what i did was |dw:1374955051895:dw|

OpenStudy (anonymous):

im not supposed to use those though @pengembara_bumi1

OpenStudy (anonymous):

i got ph as 8.95 :/

OpenStudy (frostbite):

Sorry me saying some rubbish. We use another good old relation: \[NH _{3}+H _{2}O \rightarrow NH _{4}^{+}+OH ^{-}\] \[K _{b}=\frac{ [NH _{4}^{+}] [OH ^{-}] }{ [NH _{3}] }\] Try use that instead.

OpenStudy (frostbite):

Find the hydroxide concentration and use water's self ionization constant to find the proton concentration then take the negative logarithm to find the pH. Use the constant for water at 25 degrees C.

OpenStudy (anonymous):

so i just use ice chart instead?

OpenStudy (frostbite):

ice chart? I see no need for that?

OpenStudy (anonymous):

Do you mind doing a walk through of the problem when you have the time? i think im confusing myself

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