Question

Find the magnitude and direction angle of:
v=6i+3j

round direction angle to nearest degree

Answer 1

magnitude is just sqrt(6^2+3^2)

Answer 2

for finding magnitude you must sequre root (6^2+3^2)

Answer 3

\[ \left| V \right| = \sqrt{6^2+3^2}=\sqrt{36+9}\sqrt{45}\]

Answer 4

The angle is:
Tan(theta) = 3/6

Answer 5

y component / x component

Answer 6

\[\tan \theta=\frac{ 3 }{ 6 }\]

Answer 7

tan(theta) = 1/2
theta = ArcTan(1/2)

Answer 8

about 27 degrees

Answer 9

26.56505118 lol ;)

Answer 10

s/he asked us to round it.

Answer 11

yeah was just playin ;)