let log(D^2/C^3*A) when logA=3 logB=2 logD=5
a)0.549
b)4.44
c)1
d)19

Question

let log(D^2/C^3*A) when logA=3 logB=2 logD=5 
a)0.549
b)4.44
c)1 
d)19

anonymous · Answer

$$\begin{align*}\log\left(\frac{D^2}{C^3A}\right)&=\log D^2-\log\left(C^3A\right)\
&=2\log D-\left(\log C^3+\log A\right)\
&=2\log D-3\log C-\log A\
&=\cdots
\end{align*}$$

anonymous · Answer

i did that but i got none of the four answers that they give you. please explain more

anonymous · Answer

Do you know what $\log C$ is?

anonymous · Answer

logC is 2

anonymous · Answer

Ah, so that was a typo..
$$\begin{align*}\log\left(\frac{D^2}{C^3A}\right)&=\log D^2-\log\left(C^3A\right)\
&=2\log D-\left(\log C^3+\log A\right)\
&=2\log D-3\log C-\log A\
&=2(5)-3(2)-3\
&=10-6-3\
&=\cdots 
\end{align*}$$

anonymous · Answer

yeah it was. thanks for the help

anonymous · Answer

you're welcome