Question

Please help

Which of the following is the minimum value of the equation

y=3x^2-4x-2

A. -2/3
B.2
C.3
D. -3 3/3

Answer 1

well, the way I'd go about it is
is a parabola, the leading coefficient is positive, so it goes upwards
to get the vertex for a parabola like so, you can just use \(\bf \left(-\cfrac{b}{2a}, f\left(-\cfrac{b}{2a}\right)\right)\)

I gather you only want the "x" coordinate, so just get that one

Answer 2

the vertex is how low it'd go, thus the minimum

Answer 3

hmm actaully I guess they may just want the "y", so just get the "y" :)

you can also use just for the "y" \(\bf c-\cfrac{b^2}{4a}\)

Answer 4

ok so it would be B. than

Answer 5

@jdoe0001

Answer 6

I'm not getting either

Answer 7

for "x" I get something else and "y" too

Answer 8

hmmm ok, I see my mistake

Answer 9

ok, well is not B
and they want the "x" coordinate, so what did \(\bf -\cfrac{b}{2a}\) give you?

Answer 10

would 3 be A. or no?

Answer 11

if you just solve it by using \(\bf -\cfrac{b}{2a}\) you'd know :)

Answer 12

yeah thats the thing I wasnt sure if it was 3 or -2

Answer 13

I dont mean the answer I mean what numbers do I use to solve the problem

Answer 14

woops need to dash but anyhow

y= 3x^2 -4x -2
a b c

Answer 15

@Zale101 can you help with this problem?