Question

(2x^2+10x+12)+(x+3) using synthetic division

Answer 1

need help plzz

Answer 2

ill give free medals

Answer 3

to use synthetic division, you must be dividing by (x-c) so in this case c = -3

-3 | 2 10 12
______-6___-12___
2 4 0

remainder is zero
quotient is 2x+4

Answer 4

so the answer is 2x+4 r0

Answer 5

you could have just factored here
2x^2+10+12 = 2(x+3)(x+2)

Answer 6

can you help me with more
plzzz

Answer 7

yes that is answer

Answer 8

oh thank you so much

Answer 9

i have a another one

Answer 10

\[x ^{3}+4x ^{2}-3x-12 divided by x ^{2}-3\]

Answer 11

factor

Answer 12

ok

Answer 13

you can use factor by grouping...im waiting for others to respond before i explain further

Answer 14

ok

Answer 15

lil confused

Answer 16

\[i read the statement as divide x ^{3}+4x ^{2}-3x-12 by x ^{2} -3\]

Answer 17

yeah

Answer 18

the way you set it up was confusing

Answer 19

i used long division

Answer 20

they told me to use synthetic division

Answer 21

thats polynomial division...have you learned that yet?
again its not necessary here tho

\[\frac{(x^{3}+4x^{2})+(-3x-12)}{x^{2}-3} = \frac{x^{2}(x+4)-3(x+4)}{x^{2}-3} = \frac{(x+4)(x^{2}-3)}{x^{2}-3} = x+4\]

Answer 22

no not really

Answer 23

synthetic division wont work unless its in form x-c

Answer 24

@surjithayer , you made a mistake in your long division

Answer 25

oh ok can you explain it to me then

Answer 26

i already did...i used factor by grouping to factor numerator ^^

Answer 27

ohh lol ok

Answer 28

\[x ^{2}-3=0,x ^{2}=3,x=\sqrt{3},-\sqrt{3}\]

Quoient =x+4, Remainder 0