Question

help! what is the vertex of the graph of y=5(x+4)^2

Answer 1

do you know what an equation in vertex form is?

Answer 2

no how do i change it?

Answer 3

its already in vertex form meaning you can pull the vertex out of the equation.

Answer 4

Vertex = (h,k) vertex form is y= a(x-h)^2+k

Answer 5

i know how to get the vertex out if the equation was something like y=x2 +bx+c but i dont know how for this one

Answer 6

oops i wrote the equation wrong its y=5(x+4)^2 +3

Answer 7

ok so based off this:

Vertex = (h,k)
vertex form is y= a(x-h)^2+k

what do you think the vertex is?

Answer 8

(4, 3)

Answer 9

close but no, remember to get (x+h)^2 from (x-h)^2 the h has to be negative.

Answer 10

so (-4, 3)

Answer 11

Exactly! Now you got it!