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Mathematics 16 Online
OpenStudy (anonymous):

solve

OpenStudy (anonymous):

OpenStudy (anonymous):

Cost price of 500m wire= 500*0.75=Rs375 Cost price of 300m wire= 300*0.75=Rs225 Cost price of 200m wire= 200*0.75=Rs150 as 60% sold at 8% profit the selling price of 300m wire=(225*1.08)=Rs243 as given total 500m desired to be sold at 12% profit then SP of 500m=(375*1.2)=Rs450 So 450=243+150*x where x is the required profit %age hence207=150x x=1.38 hence remaining 40% wire must be sold at 38% profit

OpenStudy (anonymous):

@heybhai how u write 300m , 200m and there should be 1.12 instead of 1.2 how this came hence remaining 40% wire must be sold at 38% profit plse tell me

OpenStudy (anonymous):

sorry i thought it was 20% profit make subsequent change and get right answer. my method is alright.just plug in right values.

OpenStudy (anonymous):

i didnt get u plse can u explain a little bit

OpenStudy (anonymous):

k let me solve again.wait a while

OpenStudy (anonymous):

@heybhai plse

OpenStudy (anonymous):

Cost price of 500m wire= 500*0.75=Rs375 Cost price of 300m wire= 300*0.75=Rs225 Cost price of 200m wire= 200*0.75=Rs150 as 60%i.e. 300m sold at 8% profit the selling price of 300m wire=(225*1.08)=Rs243 as given total 500m desired to be sold at 12% profit then SP of 500m=(375*1.12)=Rs420 So 420=243+150*x where x is the required profit %age hence177=150x therefore x=1.18 hence remaining 40% wire i.e. 200 m must be sold at 18% profit so that overall profit of 500m wire is 12%

OpenStudy (anonymous):

how 40% came

OpenStudy (anonymous):

as given 60% sold at 8% remaining is 40% as total of anything is 100%

OpenStudy (anonymous):

okay @heybhai thank u

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