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Mathematics 5 Online
OpenStudy (anonymous):

im stuck on c pl look at the file i put on pl

OpenStudy (anonymous):

i need help pl

OpenStudy (anonymous):

y=-3x+3

OpenStudy (anonymous):

thank u

OpenStudy (anonymous):

throw me a badge, dog

OpenStudy (anonymous):

I always wanted one of those

OpenStudy (anonymous):

im stuck again

OpenStudy (anonymous):

lemme take a look

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

y=-0.5

OpenStudy (anonymous):

lmk if you want me to teach you how to get the answer

OpenStudy (anonymous):

pl

OpenStudy (anonymous):

your "line of best fit" is the one line just balances out the plotted points the best. It's pretty visual at this level. Once you get into stat it gets really complicated but just keep it simple for now. Draw a line for what looks best

OpenStudy (anonymous):

your equation just looks at the basic y=mx+b (where m=slope and b=y-intercept). You follow so far?

OpenStudy (anonymous):

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

to find the y=...just plug in the mx+b. In the second example your m would just be rise/run starting from any point on that line of best fit. in the last picture you sent me (rise=-3)/(run=1) so your slope (m) would equal -3/1 or -3

OpenStudy (anonymous):

your y-intercept (b) in the exmaple you gave me is just wherever your line crosses the y-axis (line that's straight up and down). in that last picture, it crosses the y-axis at y=0. so your b=0

OpenStudy (anonymous):

put it all together and you have y=mx+b -> y=-3x+0 -> y=-3x

OpenStudy (anonymous):

OpenStudy (anonymous):

ok

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