Question

help pleaseeee

Answer 1

Alright so do you know how to plot such equations, or this is your first attempt?

Answer 2

ok first of all do you know what
\[\frac{y^2}{b^2}-\frac{x^2}{a^2}=1\] looks like ?

Answer 3

yes

Answer 4

Ok so since you are aware of the equation, do you know what does it mean when you equate the LHS to 1 in the standard equation? I mean, do you know what would happen if instead of being equal to 1 the LHS would be greater than or less than 1?

Answer 5

in this case general form is
\[\frac{y^2}{b^2}-\frac{x^2}{a^2}=1\] so \(b=9,a=7\)

Answer 6

so you just plug them in

Answer 7

asymptotes are \(y=\pm\frac{b}{a}x\)

Answer 8

for your example you get
\[y=-\frac{9}{7}x\] and \[y=\frac{9}{7}x\]

Answer 9

since the center is at the origini \((0,0)\) the vertices are 9 units above and below the center
i.e. at \((0,9)\) and \((0,-9)\)

Answer 10

i guess you need to know that since the \(y\) term comes first, it looks like htis

Answer 11

this is the example right

Answer 12

yes

Answer 13

ok

Answer 14

now you don't have
\[\frac{y^2}{9^2}-\frac{x^2}{7^2}=1\] you have \[\huge\frac{y^2}{9^2}-\frac{x^2}{7^2}>1\]

Answer 15

greater than, not "equal to" so you have to decide what part to shade, which is frankly not that hard