Question

If \(\frac{ x+3y }{ 2x-y }=\frac{ 2 }{ 3 }\) , then\(\frac{ x-y }{ x+y}\) =?

Answer 1

\[\frac{x + 3y}{2x - y} = \frac{2}{3}\]

3(x + 3y) = 2(2x - y)
3x + 9y = 4x - 2y
2y + 9y = 4x - 3x
(2 + 9)y = (4 - 3)x
11y = x
\[\frac{11}{1} = \frac{x}{y}\]

\[\frac{x - y}{x + y} = \frac{11 - 1}{11 + 1} = \frac{10}{12} = \frac{5}{6}\]

Answer 2

ohh, thanks, i know how to do now:)

Answer 3

Do you have another one?

Answer 4

That one was convenient because we were able to isolate x relatively easy.

Answer 5

These are not usually that straight forward.