Question

a^2+b^2=c^2 If a=x b=1/2x+11 and c=2x+1

Answer 1

So what is the qustion? Just put them in evaluate?

Answer 2

i dont know how

Answer 3

So that is all they told you. Nothing else? If so, then you probably need to replace a, b, and c with the things provided and thensee whatyou end up with.

Answer 4

Ah, OK. So Applying Pythagoras and saying solve for x.

Because they give you \(a^2+b^2=c^2\) if \(a=x,~ b=\tfrac{1}{2}x+11\) and \(c=2x+1\)

That means you replace a with x, b with \(\tfrac{1}{2}x+11\), and c with \(2x+1\). However, remember that is a replacement before they are squared! Then you use algebra to solve for x.

Answer 5

i need help solving for x

Answer 6

Know how to solve a polynomial? This one will become something in the form of \(\text{#}x^2+\text{#}x+\text{#}\) where the # are some numbers... they usually use a, b, and c to represent them, but your problem is using those for something else here...

Answer 7

how woulld i get rid of 2x+1
\[ x^2+\frac{ 1 }{ 2 }x+11=2x+1\]

Answer 8

Remember the squars come after the replacement:
\((x)^2+(\tfrac{1}{2}x+11)^2=(2x+1)^2\)

Answer 9

\((x)^2\) is easy. It is \(x^2\). But you need to multiply out \((\tfrac{1}{2}x+11)^2\) and \((2x+1)^2\). You may have heard that called FOIL or something like that.

Answer 10

Not against each other. Against themselves. They are squared.

Answer 11

do you mean as in 11x2 or 11x11

Answer 12

\(5^2\) is th same as saying \(5 \times 5\) right? Well, \((\tfrac{1}{2}x+11)^2\) means \((\tfrac{1}{2}x+11)\times (\tfrac{1}{2}x+11)\)

Answer 13

\((x)^2+(\tfrac{1}{2}x+11)^2=(2x+1)^2 \implies\)

\((x)^2+(\tfrac{1}{2}x+11)(\tfrac{1}{2}x+11)=(2x+1)(2x+1)\)

You have to multiply it all out before you can even start to solve for x.

Answer 14

so first


b=(x/2) +11


or b= (x+11)/2

?

Answer 15

@jhonyy9 He actually used the formatting later, so half x. But seems to have stopped replying at the moment...

Answer 16

ok

thanks

Answer 17

how would i multiply it all out?

Answer 18

Are you saying you do not know how to multiply \((\tfrac{1}{2}x+11)(\tfrac{1}{2}x+11)\)? You started to try to FOIL earlier, but just chose the wrong things. You need to FOIL \((\tfrac{1}{2}x+11)(\tfrac{1}{2}x+11)\) for one part AND FOIL \((2x+1)(2x+1)\) for a completely different part.

Answer 19

This is all because of order of operations. PEMDAS.
Parenthesis
Exponents
Multiplication and Division
Addition and Subtraction

Parenthesis is first, so I must do what is in the parenthesis before I can do anything else. However, there are variables in there, so I can't do much. I just have to keep each entire parenthetical statements together as a single unit for now.

Exponents are second. The parenthetical statements have exponents. So I need to apply the exponent to the each parenthetical statement. \((x)^2\) is easy. It is \(x^2\). However, the other two statements, \((\tfrac{1}{2}x+11)^2\) and \((2x+1)^2\), end up needing to be deal with separately. So you need to multiply out two equations just to start:

\((\tfrac{1}{2}x+11)(\tfrac{1}{2}x+11)\)
and
\((2x+1)(2x+1)\)

After you do that, you can continue.

If you are not sure how to FOIL or multiply out a polynomial, look at:

http://www.purplemath.com/modules/polymult.htm

Answer 20

This is what I got
X^2+1/4x+121=4x+1

Answer 21

Hmmm.... you seem to be missing some terms.