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review of alg 2 helpp?
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\[\frac{ 125 }{ 8 } \]
to the -2/3
if you take the cube root, you can get \(\frac{5}{2}\)
the answer is 4/25 but thats what i thought too
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ohhh
cuz it''s 2/3
\[\Large \left( \frac{ 125 }{ 8 } \right)^{-2/3} = \left( \frac{ 8 }{ 125 } \right)^{2/3} \] \[\Large \left( \frac{ 8^{1/3} }{ 125^{1/3} } \right)^{2} = \left( \frac{ 2 }{ 5 } \right)^2\] I'm sure you can finish.
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