How would I solve this with synthetic division?
\[x^3-6x^2+8x\]
Doesn't division require a second expression? Or did you mean to factor?
Sorry. The factor is 4
we're under the assumption you know synthetic division otherwise there's no good reason to assign you an exercise on it
I need help with synthetic division
\(\bf x^3-6x^2+8x \div x-4 \) I assume?
Yes
Here is a good resource: http://www.purplemath.com/modules/synthdiv.htm for many math questions.
first off, arrange all your factors in descending order by exponent so \(\bf x^3-6x^2+8x \implies x^3-6x^2+8x+0\) then line up and divide \(\begin{matrix} 4&|& 1 & -6 & 8 & 0\\ &|\\ \hline\\ & & 1 \end{matrix}\)
I know how to set up the division, i just don't know how to do it.
well, as the url by gypsy1274 shows you "drop" the 1st coefficient then multiply the left-side, in this case 4, times the "dropped" number the product will go under the following coefficient and will add up with it in this case the following coefficient is -6 and from the sum, you'd get some other number under the line and do the same to the end
Thanks m8
\(\begin{matrix} 4&|& 1 & -6 & 8 & 0\\ &|&&4\\ \hline\\ & & 1&-2 \end{matrix}\)
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