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OpenStudy (anonymous):
Get your x terms to the left side and your constant terms to the right side.
OpenStudy (anonymous):
okay @gypsy1274 ??
OpenStudy (anonymous):
Using inverse operations. If the term is positive, then subtract it from both sides. If the term is negative, then add it to both sides.
OpenStudy (anonymous):
If you had:
\(2x+3=15\)
You would subtract 3 from both sides to get:
\(2x=12\)
OpenStudy (anonymous):
okay @gypsy1274
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OpenStudy (anonymous):
What did you come up with?
OpenStudy (anonymous):
8x =4??
OpenStudy (anonymous):
Close.
\(5x-5=3x-9\)
The x terms in this equation are positive which means that you will need to subtract to get the \(+3x\) to the other side of the equation.
\(5x-3x=?\)
OpenStudy (anonymous):
2z
OpenStudy (anonymous):
2x?
So you now have:
\(2x-5=-9\)
What do you do next?
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OpenStudy (anonymous):
add 5 to get 2z = -4?? which will give x= -2
OpenStudy (anonymous):
Yes. Except that you z should be an x. The variable name will make a bigger difference when you start working with more variables in the equation.