Question

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer.)
3tan^3 θ = tan θ

Answer 1

Well, let's do some algebra on this thing and see where it takes us:

\[3\tan ^{3}\theta = \tan \theta \]
Divide by 3tan(theta)
\[\tan ^{2}\theta = \frac{ 1 }{ 3 }\]
Now we'll square root both sides.
\[\tan \theta = \pm \sqrt{\frac{ 1 }{ 3 }} \]
This can be simplified to:
\[\tan \theta = \pm \frac{ \sqrt{3} }{ 3 }\]
Think you could take it from there?

Answer 2

tan(30 deg)=1/((sqrt)3)
theta =30deg.