Question

Indicate in standard form the equation of the line passing through the given points.

R(3, 3), S(-6, -6)

Answer 1

Do you know how to get the slope?

Answer 2

No I dont That is what I need help with

Answer 3

okay to find the slope you use the equation \[y ^{2}-y ^{1}\div x ^{2}-x ^{1}\]

Answer 4

can you do that for me?

Answer 5

yes give me a minute

Answer 6

-6-3 divided by -6-3

Answer 7

yes so the slope is 1, now use the formula \[y-y ^{1}=m(x-x ^{1})\]

Answer 8

-6-3=-9m(-6-3=-9

Answer 9

actually it is \[y-3=1(x-3) \] solve for slope intercept form, do you know what that is?

Answer 10

i am sorry i dont i have a really hard time in math but i am willing to figure it out

Answer 11

okay lets start from the beginning,

You are trying to find the standard form equation of a line running in between the points, (3,3) & (-6,-6). Standard form is Ax+By=C and the equation i gave you before is to get y=mx+b, which is the equation you get before standard form.

Are you good so far?

Answer 12

Yes I am

Answer 13

So you using the equation \[y-3=1(x-3)\] becomes y-3=1x-3. Now isolate y by itself and what do you get?

Answer 14

Y-3

Answer 15

Your answer becomes y=1x+0, because you add 3 to both sides to get y on one side.

Answer 16

so that is the answer?

Answer 17

Now to get standard form, Ax+By=C.

Subtract 1x from each side to get -1x+y=0
(change all the signs when the leading term is negative)
Your answer is x-y=0