Question

4v^2+15v-4 factor by grouping?

Answer 1

So you have an equation in the form of ax^2 + bx + c. In order to factor this, you first need to find factors of a*c that will add up to b. In this case, your a is 4 and your c is -4, multiplied this becomes -16. So now you need to find factors of -16 that will add up to b, which is +15 in this case.

Answer 2

I forgot to factor 16. so I would have (4v^2-1v)+(16-4)?

Answer 3

Right :3 Just dont forget the v with 16 there.

Answer 4

okay so... my final answer would be (2v+4)(2v-1)???

Answer 5

Hmm...I believe we grouped wrong. Try (4v^2+16v) (-1v-4) :3

Answer 6

2v(2v+8) for the first one?

Answer 7

Fact out another 2 :P

Answer 8

see im confused now! LOL sorry

Answer 9

No worries. Sorry, hopping around a bit. Okay, you want the LARGEST number that can factor out of both terms. You have a 4 and a 16. Well, both are not only divisible by 2, but by 4 as well. So you needed to factor out a 4, not just a 2

Answer 10

its okay. I appreciate the help! so I would actually have 4v(v+4)

Answer 11

Right :3. Which means there should be a way to get v+4 in theother parenthesis, too.

Answer 12

that leaving me with (4v+4)(v+4)

Answer 13

Well, you have 4v(v+4) and (-1v-4). So from here, you actually need to take out a -1 from the second one. So you would actually have 4v(v+4) and -1(v+4)

Answer 14

that makes much better sense! thank you again!!!

Answer 15

Mhm, np.