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Mathematics 9 Online
OpenStudy (anonymous):

Find derivative with respect to x.

OpenStudy (anonymous):

OpenStudy (amistre64):

\[\frac d{dx}f(x)=\lim_{h\to 0}\frac{f(x+h)-f(x)}{h}\] :)

OpenStudy (anonymous):

The question is in the attachment!

OpenStudy (amistre64):

just pull the bottom up and you have a 3term product rule

OpenStudy (anonymous):

Yup....dont know the thre term product rule...Can ya give me??I know upto 2 product rule!!

OpenStudy (anonymous):

*three

OpenStudy (amistre64):

\[y = a^2b^{-3}c^{-4}\] \[y' = 2ab^{-3}c^{-4}-3a^2b^{-4}c^{-4}-4a^2b^{-3}c^{-5}\]

OpenStudy (amistre64):

the product rule just makes "n" copies and runs a derivative on one term in each

OpenStudy (anonymous):

In terms of x and n(s)!!

OpenStudy (amistre64):

i used abc as the functions ... since they are all linear to begin with they just pop out 1s so just follow the pattern

OpenStudy (anonymous):

k...any easier method???shorcut??

OpenStudy (anonymous):

It'll be laborius for competitive xams!!

OpenStudy (amistre64):

\[f=g_1g_2g_3...g_n\] \[f'=(g'_1g_2g_3...g_n)+(g_1g'_2g_3...g_n)+(g_1g_2g'_3...g_n)+...+(g_1g_2g_3...g'_n)\] calculating things IS laborious :) you can go with expanding the bottom and running the quotient

OpenStudy (anonymous):

Can substitution help here??

OpenStudy (amistre64):

lol, i substituted with abc ... so if youre not into that then no

OpenStudy (anonymous):

k....then dat will do,I guess....tnx

OpenStudy (amistre64):

good luck ;)

OpenStudy (anonymous):

tnx agn!!Cheers!

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