what is the sum of a 14-term arithmetic sequence where the last term is 30 and the common difference is -5?
do you want me to like show my work? or do you just want the answer?
work please!
ok so the arithmetic sequence equation is: a_n=a_1 + (n-1)d
okay
since you dont have the first term to plug into the equation you plug what you have in and solve for a_1 first what do you get?
after you get the a_1 then you can use the arithmetic Series equation: s_n =n/2[2a_1+(n-1)d] to find the sum
so a_n=30 n=14 d=-5
30=a_1+ (14-1)-5 30=a_1+(13)-5 30=a_1+(-65) 30=a_1-65 95=a_1
So since you have a_1 now you plug it into the arithmetic series equation to find the sum
so S_n=14/2[2(95)+(14+1)-5] S_n=7[190+(15)-5] S_n=190-75 S_n=115
So the answer is 115
Do you understand it?
no still confused the answers is either: 875 812.5 455 422.5
Is the problem right that you typed? cause i did my math right so is anything different?
if the common difference is not negative it will be very different
the question is written right, i'm confused because i got the same answer you did. but 115 isn't one of the answers i can choose from ?
Hmm. thats odd :l none of the answers can be "none of the above"?
no those are the only ones i can choose.
ok hold on a second ill do my math again 805 an answer?
no
its 875 if you use the other equation for the sum : S_n=n/2(a_1+a_n) S_n=14/2(95+30) S_n=7(125) S_n=875
okay, thank you so much!
No problem! lol
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