Question

factor:
show steps:
see below:

Answer 1

\[169y ^{2}-64x ^{2}\]

Answer 2

What's common in this? @Algebra2013

Answer 3

=??\[(13y-8x)(13y+8x)\]

Answer 4

I got 13 and 8 as common

Answer 5

do you agree?

Answer 6

What did you take common in this
169y^3-64x^2?

Answer 7

its 169^2

Answer 8

oh I see the y and x. So the answer is not factorable correct

Answer 9

ya 169^2*

Answer 10

the y and x are not common meaning problem not factorable

Answer 11

wait I'm lost and confused

Answer 12

please explain

Answer 13

I dont think so 169 and 64 come in any table together.

Answer 14

I got (13y-8x)(13y+8x)

Answer 15

do you agree?

Answer 16

13*13=169
8*8=64

Answer 17

I know but they don't come in any table together..

Answer 18

by table you mean?

Answer 19

http://www.wolframalpha.com/input/?i=169y%5E2+-64x%5E2%3F

Answer 20

table?

Answer 21

ok please help me explain

Answer 22

oh wow. so the negative is on the outside

Answer 23

hey uri why are you holding him?

Answer 24

let me explain

Answer 25

Sure.

Answer 26

please do

Answer 27

no your answer is perfectly alright

Answer 28

I've only been on this problem for 20 minutes now

Answer 29

are you serious???????

Answer 30

your answer is correct!

Answer 31

ok thanks.
its a bit confusing

Answer 32

I have another problem giving me trouble with the positive

Answer 33

(13y-8x)(13y+8x) expand this out ..and yout get 169y^2 + 104xy -104xy -64x^2 ..so good job!

Answer 34

Do we do it like this
169y^2-64x^2
13y(13y)-8x(8x)
(13+8x)(13y-8x)

Answer 35

^uri no we definitely dont..but you cant say he is wrong :)

Answer 36

wut.

Answer 37

^what are you getting?

Answer 38

@Algebra2013 you can also write the way wolfram did..but you will have to put a minus in front then ..expand their solution..you will get the same thing..cheers!

Answer 39

I did it right...@PrincetonTiger

Answer 40

^yes you missed a y though :)

Answer 41

I'ts a typo sir.

Answer 42

okay :)