A firecracker shoots up from a hill 165 feet high with an initial speed of 110 feet per second. Using the formula H(t) = −16t2 + vt + s, determine how long it will take the firecracker to hit the ground. 7.2 seconds 7.5 seconds 7.8 seconds 8.1 seconds
But firecrackers just explode...they don't fly into the sky...Bottlerockets fly in the sky! :-)
not the bit explozives the shoot up and pop in the air and the scraps come back down con u help
whats t then or do I have to find t
Yes, that's the only variable left. Without it, we would have numbers only and nothing to solve for :D
so the equation would look like 165=-16²+vt+s
165=-16t+110t+0
how would I start would I start with the exponent or the 110
Hang on a minute please.
You have to set it up as a quadratic equation...however, I need to check to make sure we have the correct values for all the variables.
Okay...
ok
H(t) = final height = 0 v = speed of firecracker = 110 s = initial height = 165 So the correct setup is 0 = -16t^2 + 110t + 165
ok that make more sense bc it has it = 0
next I think I have to find a gcf and divide by that or divide by 16
It doesn't always have to be = 0. But I guess if it wasn't you would have to use additional equations.
When solving quadratic equations, if you have a negative for the leading term, you'll want to try to get rid of it. There are two ways to do it. You can either add each term to the other side of the equation, or you factor out a negative: 0 = -(16t^2 - 110t - 165) Then divide both sides by -1: 0 = 16t^2 - 110t - 165
It is probably best to use the quadratic formula to find t in this case.
can u tell me what the 1st step is to solve it then im pretty sure I can solve it form there I just need help getting started
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