Question

if log2=0.301 and log3=0.477, then the number of digits in 6^20 is

Answer 1

well using log laws 1st deal with the exponent

\[\log(x^a) = alog(x) \]

apply the above law to the exponent of 20

and the law for multiplication is

\[\log(xy) = \log(x) + \log(y) \]

where x and y are factors of xy.

does this make sense.... ?