Question

15=5^(x+3)-7 please help

Answer 1

subtract 7 from both sides

Answer 2

well, add rather :/

Answer 3

then

Answer 4

\(\bf 15=5^{x+3}-7 \implies 22 = 5^{x+3}\\
\textit{log cancellation rule of } log_aa^x = x\\
log_5{22} = log_5(5^{x+3}) \implies \square? = \square?\)

Answer 5

or lemme put it this way
\(\bf log_\color{red}{a}\color{red}{a}^x = x \implies log_\color{red}{5}(\color{red}{5}^{x+3}) = \square?\)