(X-4)^2+4(X-4)-12=0
X^2+4X-12
(X+6)(X-2)
X=-6,2
(X-4)-6=0
(X-4)+2=0
X-4=6...X=10?
X-4=-2....X=2

Question

(X-4)^2+4(X-4)-12=0
X^2+4X-12
(X+6)(X-2)
X=-6,2
(X-4)-6=0
(X-4)+2=0
X-4=6...X=10?
X-4=-2....X=2

psymon · Answer

Are we just checking your answer?

anonymous · Answer

$$X^ \frac{ 1 }{ 2 } + \sqrt{3X}^\frac{ 1 }{ 4 }-18$$

psymon · Answer

This is a little tricky, but it is still a quadratic and still is in the form of ax^2 + bx + c. If you notice, the power on the leading x is the same x^(1/4) squared. If that makes any sense. You see how?

anonymous · Answer

YES , IM STUCK ON SQRT3X BEING FACTORED WITH THE 18

psymon · Answer

Just by chance, you don't have a multiple choice thing, right? Just curious if the answer is supposed tobe funky.

anonymous · Answer

NOPE

psymon · Answer

Lots of caps o.o

anonymous · Answer

sorry

psymon · Answer

Well, because it's a square root 3, it looks like this is quadratic formula for sure. It's just being able to realize that it is a quadratic first.

anonymous · Answer

it is a Quadratic

psymon · Answer

I know.....sorry, didn't mean anything by saying that....either way, quadratic formula:

psymon · Answer

$$\frac{ -(3^{\frac{ 1 }{ 4 }})\pm \sqrt{(3^{\frac{ 1 }{ 4 }})^{2}-4(-18)}  }{ 2 }$$

Now it's just simplifying that mess as much as possible.