Question

Which factor can you cancel from the numerator and denominator to simplify 8 minus 2 times x all over 3 times x minus 12.? [Hint: (a−x) = − (x − a)]

2 over 3.

3 over 2.

x − 4

x + 4

Answer 1

\[\frac{8-2x}{3x-12}\]
Did you try @jaderbrown

Answer 2

yeah it's either c or d im sure

Answer 3

Can you take any common term out of the numerator?
\[(8-2x)\]

Answer 4

2

Answer 5

good, what would you get? could you bring 2 out? and write what would you get

Answer 6

I'm confused, what do you mean?

Answer 7

Can you bring out 2 from numerator?

Answer 8

yes?

Answer 9

And what would you get then? I mean the numerator

Answer 10

2 over 3

Answer 11

I mean like this
\[8-2x\]
=>\[2(4-x)\]

Answer 12

alright then what?

Answer 13

Now, we have to do the same thing with the denominator. Take out common factor from denominator and write the expression you get

Answer 14

3(3-x)?

Answer 15

you have 3x-12
Take out 3 from this. I'll simplify it a bit for you
\[3\times x -3\times 4\]

Answer 16

alright now what?

Answer 17

Please bring 3 out from this
\[3x-3\times 4\]

Answer 18

3x-12

Answer 19

@jaderbrown We have to bring a common 3 out from both ther terms
\[3x-12\]
\[(3\times x -3\times 4)\]
\[3(x-4)\]
Do you understand this part?

Answer 20

yes

Answer 21

so now what

Answer 22

Now we have
\[\frac{2(4-x)}{3(x-4)}\]
do you see any common factor?

Answer 23

4

Answer 24

x+4

Answer 25

We can write
\[(4-x)=-(x-4)\]
so
\[\frac{2(4-x)}{3(x-4)}=\frac{-2(x-4)}{3(x-4)}\]
do you follow this?

Answer 26

yes

Answer 27

So we see
\[\frac{-2\underline{(x-4)}}{3\underline{(x-4)}}\]
any common factor?

Answer 28

x-4

Answer 29

yes, you're right. Did you understand?

Answer 30

yes thank you