Find the exact value by using a half-angle identity. sin ( 7 pi / 8 )
Do you know what the half angle identity is?
Yeah
sin(7pi/8) = sin((7pi/4)/2), right? sin(u/2) = sqrt((1-cos(u)/2) = sqrt((1-cos(7pi/4))/2 8pi/4 is a full circle. 7pi/4 is 45° below the x axis, so cos(7pi/4) = sqrt(2/2), so sin(7pi/8) = sqrt((1-sqrt(2)/2)/2) = sqrt(1/2-sqrt(2)/4) = 0.38 Since 7pi/8 is above the x axis, the sin is positive, so the full answer is sin(7pi/8) = +0.38. Plugging into my calculator and computing the sin directly, I confirm that this answer is correct.
\[\cos 2x = 1-2 \sin^{2} x\] \[\cos \frac{7\pi}{4} = 1-2\sin^{2} \frac{7\pi}{8}\] \[\frac{\sqrt{2}}{2} = 1-2\sin^{2} \frac{7\pi}{8}\] \[2\sin^{2} \frac{7\pi}{8} = 1-\frac{\sqrt{2}}{2} = \frac{2-\sqrt{2}}{2}\] \[\sin \frac{7\pi}{8} = \frac{\sqrt{2-\sqrt{2}}}{2}\]
Why do people ask such dumb questions, this doesn't help anything
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