Question

factor out completely:
see below:

Answer 1

\[2z ^{5}+2x-yz ^{5}-xy\]

Answer 2

first, factor out the x to possible terms, and factor out the z^5 to possible terms.

Answer 3

x(2-y)+z^5(2-y)= (2-y)(x+z^5)

Answer 4

(2z-

Answer 5

I am lost

Answer 6

please explain (2-y)

Answer 7

Lets rearrange it. first.

Answer 8

lets make it to 2x-xy+2z^5-yz^5

Answer 9

check I understand

Answer 10

then from the first and second term, you see that both two terms have x, and from third and fourth term, you see that both terms have z^5. so you factor them out.

Answer 11

oh ok 2-y

Answer 12

you will have x(2-y)+z^5(2-y). you can now factor out (2-y) together because both terms have it, and group the remainders. this gives (2-y)(x+z^5)

Answer 13

oh oh ok got it