How much energy (in kilojoules) is needed to heat 3.10g of ice from -10.5∘C to 22.5∘C? The heat of fusion of water is 6.01kJ/mol, and the molar heat capacity is 36.6 J/(K⋅mol) for ice and 75.3 J/(K⋅mol) for liquid water.

Question

aaronq · Answer

you have to find 3 things, then add them all up.

1) heat required to raise the T of ice from -10.5 to 0 
2) heat required to melt the ice.    use: q=n*H(fusion)   ; H(fusion)=6.01kJ/mol
3) heat required to raise the T of the water from 0 to 22.5

for 1) & 3) use: q=m*C*dT   where, dT=T(final)-T(initial)

q = heat
m= mass
C=specific heat capacity