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Mathematics 8 Online
OpenStudy (anonymous):

Factor completely: 14bx^2 − 7x^3 − 4b + 2x

OpenStudy (anonymous):

\[14bx^2 − 7x^3 − 4b + 2x \] the common factors from 14 for this are 7 and 2 \[(7 x^2-2) (2 b-x)\] But 2 as a constant stays the same since it is prime...

OpenStudy (anonymous):

Thank you

OpenStudy (anonymous):

You're welcome!

OpenStudy (anonymous):

Can I ask you somethin on here? YOU cause haha I kinda wanna help somebody and your maaad smart so am allowed to ask?

OpenStudy (anonymous):

I guess so?

OpenStudy (anonymous):

not A ....

OpenStudy (anonymous):

B is your answer

OpenStudy (anonymous):

Your the best O__O

OpenStudy (anonymous):

K, bye

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