Question

Factor completely: 14bx^2 − 7x^3 − 4b + 2x

Answer 1

\[14bx^2 − 7x^3 − 4b + 2x \] the common factors from 14 for this are 7 and 2 \[(7 x^2-2) (2 b-x)\] But 2 as a constant stays the same since it is prime...

Answer 2

Thank you

Answer 3

You're welcome!

Answer 4

Can I ask you somethin on here? YOU cause haha I kinda wanna help somebody
and your maaad smart so am allowed to ask?

Answer 5

I guess so?

Answer 6

not A ....

Answer 7

B is your answer

Answer 8

Your the best O__O

Answer 9

K, bye