Find the exact value of the radical expression in simplest form.

Question

ja1 · Answer

$$\sqrt{16y^3} - \sqrt{y^3}$$

BTW those exponents are 3's...

ja1 · Answer

@dumbcow @ganeshie8 @radar

ja1 · Answer

@zepdrix @kropot72

anonymous · Answer

You essentially want to look inside each of the radical signs, and see if you can factor out any perfect squares. If you can factor out a perfect square, then you can take its square root and put it in front. 

For example, look at the first radical:
$$\sqrt{16y^3}$$16 is a perfect square. It's square root is 4, so we can move the 4 into the front like this:
$$4\sqrt{y^3}$$

ja1 · Answer

OH ok I see, I did it the wrong way, so that means it will be:

$$4\sqrt{y^3} - \sqrt{y^3}$$

ja1 · Answer

Which would make:

$$3\sqrt{y^3}$$

anonymous · Answer

Right. We can go one step further though, because theres a perfect square factor of y^3. Can you figure out what it is?

ja1 · Answer

$$y \sqrt{y}$$

ja1 · Answer

?

anonymous · Answer

Right. So your final answer would be 
$$3y \sqrt{y}$$

Sorry for not responding, for some reason I didn't get a notification that you replied

ja1 · Answer

Yah OS has been having major issues today with the tier level and notifications, hopefully it will get fixed soon! Anyways thanks for helping, I got confused on this one :)

anonymous · Answer

No problem, glad I could help

ja1 · Answer

:)