Question

i need help with this problem on my summer packet

Answer 1

what's your question

Answer 2

the problem is to simplify absolute value of x-1 divided by x-1 multiplied by x +3

Answer 3

where does the absolute value stop

Answer 4

the absolute value is only around the x-1 in the numerator of the fraction

Answer 5

ok thanks

Answer 6

does it give any conditions on x?

Answer 7

yes it says if x<1

Answer 8

ok so if x < 1, then x - 1 < 0

Answer 9

which means that we use the negative version of |x-1|

Answer 10

basically |x-1| = -(x-1) if x < 1

Answer 11

so...

|x-1|/(x-1) * (x+3)

-(x-1)/(x-1) * (x+3)

-1*(x+3)

-1*x - 1*3

-x - 3

Answer 12

wait im confused on where the negative 1 comes in

Answer 13

which line doesn't make sense

Answer 14

the third line

Answer 15

oh well (x-1)/(x-1) simplifies to 1 since any number divided by itself is 1

ie

x/x = 1

where x is NOT equal to 0

Answer 16

so that means -(x-1)/(x-1) simplifies to -1

Answer 17

oh okay thank you so much

Answer 18

you're welcome