Question

@phi find the sum 2 root 6, root 24

Answer 1

\[ 2\sqrt{6} + \sqrt{24} \]

the idea is the sqr(24) might be simplified. I would factor the 24 and look for pairs of numbers to "pull out" of the square root.

Answer 2

4 root of 3

Answer 3

how ?

Answer 4

2 rt 6 is actually same as rt 24
So?
When you add them you get their double! :)
Ans: 4 rt 6! :D

Answer 5

nvm could I have a answer choice of being 2 root6, 4 root 3!

Answer 6

are you saying you can't notice that 24 is 2*12, or 2*2*6 (we could go further)
but sqr(2*2*6) has a pair of 2's
you can pull out the pair, and write 2 in front: 2sqr(6)

now you can combine like terms

Answer 7

13 root 6?

Answer 8

\[ 2\sqrt{6} + \sqrt{24} \\ 2\sqrt{6} + \sqrt{2\cdot 2\cdot 6} \\2\sqrt{6} + 2\sqrt{6}\]

Answer 9

count how many sqr(6)'s you have : 2+2 is ?

Answer 10

you do know
\[ 2 \sqrt{6} \text{ means } \sqrt{6}+\sqrt{6} \]
you have 2 sqr(6)'s
add 2 more
how many do you have all together ?

Answer 11

4 root 6

Answer 12

@mary.rojas

Answer 13

yes

Answer 14

What are you stuck on? all? some?

Answer 15

I don't understand the problem at all

Answer 16

do you understand that
\[ 2\sqrt{6}+2\sqrt{6} = 4\sqrt{6}\]
?

Answer 17

yes, just a little bit, sorry for taking time im a visual learner and its hard to read it and understand it

Answer 18

you should think about this general idea:

2 of "something" plus 2 more of "something" is 4 "something"

that works for something being cows, horses, (x+3), \( \sqrt{6} \) and so on