Question

Squareroot :) help me.. thank you :D

Answer 1

Common denominator

Answer 2

\[\frac{1}{p+\sqrt{p^2-2p}}+\frac{1}{p -\sqrt{p^2-2p}}\]
\[\frac{1}{p+\sqrt{p^2-2p}}(\frac{p -\sqrt{p^2-2p}}{p -\sqrt{p^2-2p}})+\frac{1}{p -\sqrt{p^2-2p}}(\frac{p +\sqrt{p^2-2p}}{p +\sqrt{p^2-2p}})\]

Answer 3

@.Sam. what is the simplify ? can you explain to me how to simplify the rule after operates of \[( p - \sqrt{p ^{2} - 2p }) + (p + \sqrt{p ^{2} - 2p } )\]

Answer 4

You have to make both the denominator same to combine them into a fraction,
\[\color{red}{\frac{1}{p+\sqrt{p^2-2p}}}+\color{blue}{\frac{1}{p -\sqrt{p^2-2p}}}\]
\[=\color{red}{\frac{1}{p+\sqrt{p^2-2p}}}\times (\frac{p -\sqrt{p^2-2p}}{p -\sqrt{p^2-2p}})+\color{blue}{\frac{1}{p -\sqrt{p^2-2p}}}\times (\frac{p +\sqrt{p^2-2p}}{p +\sqrt{p^2-2p}})\]
\[=\frac{(p-\sqrt{p^2-2p})+(p+\sqrt{p^2-2p})}{p^2-(p^2-2p)}\]
Can you continue it now?

Answer 5

no.. I don't know the rule to times it. There was square on square root, I'm not understand :( can you help me, please ?

Answer 6

What happened? Still having problem?